CBSE Class 9 Maths Ch8 Quadrilaterals Notes PDF Download

Anushka
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February 23, 2026

Quadrilaterals form an important part of geometry in Class 9. In this chapter, students study different types of quadrilaterals, their properties, important theorems and conditions to prove whether a figure is a parallelogram.

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Understanding this chapter from class 9 maths syllabus clearly is important because many proof-based questions and reasoning problems in exams are asked from here.

S.No Table of Content
1. Definition of a Quadrilateral
2. Types of Quadrilaterals
3. Angle Sum Property of Quadrilateral
4. Conditions for a Quadrilateral to be a Parallelogram
5. Midpoint Theorem
6. Summary
7. Conclusion

Definition of a Quadrilateral

A quadrilateral is a polygon having four sides, four angles and four vertices.

  • The sum of the four angles of any quadrilateral is always 360Β°.
  • Quadrilaterals can be classified into various types depending on the nature of their sides and angles.

Angle Sum Property: ∠A + ∠B + ∠C + ∠D = 360°

Types of Quadrilaterals

Quadrilaterals are classified based on sides, angles and diagonals.

1. Trapezium

A quadrilateral in which one pair of opposite sides is parallel is called a trapezium.

Properties:

  • One pair of opposite sides parallel
  • Adjacent angles between parallel sides are supplementary (sum = 180Β°)
  • In an isosceles trapezium, non-parallel sides are equal

2. Parallelogram

A quadrilateral in which both pairs of opposite sides are parallel is called a parallelogram.

Derivation:

In Ξ”ABC and Ξ”CDA

AC = AC [Common / transversal]

∠BCA = ∠DAC [alternate angles]

∠BAC = ∠DCA [alternate angles]

Ξ”ABC β‰… Ξ”CDAΒ  [ASA rule]

Hence, AB = DC and AD = BC [C.P.C.T]

Properties:

  1. Opposite sides are equal and parallel.

In parallelogram ABCD,

ABβ€–CD; and AC is the transversal; hence, ∠1 = ∠3….(1) (alternate interior angles)

BCβ€–DA; and AC is the transversal; hence, ∠2 = ∠4….(2) (alternate interior angles)

Adding (1) and (2)

∠1 + ∠2 = ∠3 + ∠4

∠BAD = ∠BCD and similarly, ∠ADC = ∠ABC

  1. The diagonals bisect each other.

InΒ  Ξ”AOB and Ξ”COD, ∠3 = ∠5 [alternate interior angles], ∠1 = ∠2Β  [vertically opposite angles], and AB = CD [opp. sides of parallelogram]

Ξ”AOB β‰… Ξ”COD [AAS rule]

OB = OD and OA = OC [C.P.C.T]

Hence, proved. Conversely, if the diagonals of a quadrilateral bisect each other, then it is a parallelogram.

  1. Each diagonal divides the parallelogram into two congruent triangles.

In Ξ”ABC and Ξ”CDA,

AB = CD [Opposite sides of parallelogram]

BC = AD [Opposite sides of parallelogram]

AC = AC [Common side]

Ξ”ABC β‰… Ξ”CDA [by SSS rule]

Hence, proved.

Important Results of Parallelogram

  • Opposite sides of a parallelogram are parallel and equal.

AB || CD, AD || BC, AB = CD, AD = BC

  • Opposite angles of a parallelogram are equal adjacent angles are supplementary.

∠A = ∠C, ∠B = ∠D; ∠A + ∠B = 180°, ∠B + ∠C = 180°, ∠C + ∠D = 180°, ∠D + ∠A = 180°

  • A diagonal of parallelogram divides it into two congruent triangles.

Ξ”ABC β‰… Ξ”CDA [With respect to AC as diagonal]

Ξ”ADB β‰… Ξ”CBD Β  [With respect to BD as diagonal]

  • The diagonals of a parallelogram bisect each other.

AE = CE, BE = DE

∠1 = ∠5 (alternate interior angles)

∠2 = ∠6 (alternate interior angles)

∠3 = ∠7 (alternate interior angles)

∠4 = ∠8 (alternate interior angles)

∠9 = ∠11 (vertically opp. angles)

∠10 = ∠12 (vertically opp. angles)

3. Rhombus

A parallelogram in which all four sides are equal is called a rhombus.

Properties:

  • All sides are equal.
  • Opposite angles are equal.
  • Diagonals bisect each other at right angles.
  • Each diagonal bisects the opposite angle.

Proof: Diagonals bisect each other at right angles.

In Ξ”AOD and Ξ”COD,

OA = OC [Diagonals of parallelogram bisect each other]

OD = OD [Common side]

AD = CD [Adjacent sides of a rhombus]

Ξ”AOD β‰… Ξ”COD [SSS rule]

∠AOD = ∠DOC [C.P.C.T]

∠AOD + ∠DOC = 180° [∡ AOC is a straight line]

Hence, ∠AOD = ∠DOC = 90°

4. Rectangle

A parallelogram in which all angles are right angles (90Β°) is called a rectangle.

Properties:

  • Opposite sides are equal and parallel
  • All angles are 90Β°
  • Diagonals are equal and bisect each other

Proof: Diagonals are equal and bisect each other.

In Ξ”ABC and Ξ”BAD,

AB = BA [Common side]

BC = AD [Opposite sides of a rectangle]

∠ABC = ∠BAD [Each = 90° ∡ ABCD is a Rectangle]

Ξ”ABC β‰… Ξ”BAD [SAS rule]

∴ AC = BD  [C.P.C.T]

Consider Ξ”OAD and Ξ”OCB,

AD = CBΒ  [Opposite sides of a rectangle]

∠OAD = ∠OCB  [∡ AD || BC and transversal AC intersects them]

∠ODA = ∠OBC  [∡ AD || BC and transversal BD intersects them]

Ξ”OAD β‰… Ξ”OCB [ASA rule]

∴ OA = OC  [C.P.C.T]

Similarly we can prove OB = OD

5. Square

A rectangle with all four sides equal is called a square.

Properties:

  • All sides are equal.
  • All angles are 90Β°.
  • Diagonals are equal, bisect each other at right angles and bisect opposite angles.

Proof: Diagonals are equal, bisect each other at right angles and bisect opposite angles.

In Ξ”ABC and Ξ”BAD,

AB = BA [Common side]

BC = AD [Opposite sides of a Square]

∠ABC = ∠BAD [Each = 90° ∡ ABCD is a Square]

Ξ”ABC β‰… Ξ”BAD [SAS rule]

∴ AC = BD  [C.P.C.T]

Consider Ξ”OAD and Ξ”OCB,

AD = CBΒ  [Opposite sides of a Square]

∠OAD = ∠OCB  [∡ AD || BC and transversal AC intersects them]

∠ODA = ∠OBC  [∡ AD || BC and transversal BD intersects them]

Ξ”OAD β‰… Ξ”OCB [ASA rule]

∴ OA = OC  [C.P.C.T]

Similarly we can prove OB = OD

In Ξ”OBA and Ξ”ODA,

OB = OD Β  [proved above]

BA = DAΒ  [Sides of a Square]

OA = OAΒ  [ Common side]

Ξ”OBA β‰… Ξ”ODA,Β  [ SSS rule]

∴ ∠AOB = ∠AOD  [ C.P.C.T]

But, ∠AOB + ∠AOD = 180°  [ Linear pair]

∴ ∠AOB = ∠AOD = 90°

6. Kite

A quadrilateral in which two pairs of adjacent sides are equal is called a kite.

Properties:

  • Two pairs of adjacent sides are equal.
  • One pair of opposite angles (between unequal sides) is equal.
  • Diagonals intersect at right angles.
  • One diagonal bisects the other.

Angle Sum Property of Quadrilateral

The sum of the four angles of a quadrilateral is always 360Β°.

Proof:

Angle sum property = Sum of angles in a quadrilateral is 360Β°

In β–³ADC,

∠1 + ∠2 + ∠4 = 180Β° (Angle sum property of triangle)…………….(1)

In β–³ABC,

∠3 + ∠5 + ∠6 = 180Β° (Angle sum property of triangle)………………(2)

(1) + (2):

∠1 + ∠2 + ∠3 + ∠4 + ∠5 + ∠6 = 360°

I.e, ∠A + ∠B + ∠C + ∠D = 360°

Hence proved

Conditions for a Quadrilateral to be a Parallelogram

A quadrilateral will be a parallelogram if:

  1. Both pairs of opposite sides are equal.
  2. Both pairs of opposite angles are equal.
  3. Diagonals bisect each other.
  4. One pair of opposite sides is both equal and parallel.

If any one of these conditions holds true, then the quadrilateral is a parallelogram.

Midpoint Theorem

The line segment joining the midpoints of two sides of a triangle is parallel to the third side and equal to half of it.

Β 

In Ξ”ABC, E is the midpoint of AB; F is the midpoint of AC

Construction: Produce EF to D such that EF = DF.

In Ξ”AEF and Ξ”CDF,

AF = CFΒ  [ F is the midpoint of AC]

∠AFE = ∠CFD  [ V.O.A]

EF = DF [ Construction]

∴ Ξ”AEF β‰… Ξ”CDF [SAS rule]

Hence,

∠EAF = ∠DCF….(1)

DC = EA = EBΒ  [ E is the midpoint of AB]

DCβ€–EAβ€–AB [Since, (1), alternate interior angles]

DCβ€–EB

So EBCD is a parallelogram

Therefore, BC = ED and BCβ€–ED

Since, ED = EF + FD = 2EF = BC  [ ∡ EF = FD]

We have,EF = 12BC and EF || BC

Hence proved.

Summary

  • A quadrilateral has four sides, four vertices and four angles.
  • The sum of all interior angles of a quadrilateral is always 360Β°.
  • Special quadrilaterals include trapezium, parallelogram, rectangle, rhombus, square and kite.
  • Parallelograms have unique properties of parallel sides, equal opposite sides and angles and bisecting diagonals.
  • Different quadrilaterals are classified based on side lengths, angles and diagonals.

Conclusion

Quadrilaterals may look tough at the beginning, but with the right guidance, they become one of the easiest and most interesting topics in Class 9 mathematics.Β 

These notes have been written in simple words and short explanations, so that even stressed students can learn without feeling burdened.

So, whenever you revise, keep these notes beside you and practice regularly. With the help of this guide, you will not only perform well in exams but also start enjoying mathematics more.Β 

FAQs

Q1. State the properties of a parallelogram.

Ans. In a parallelogram, the opposite sides are parallel and equal, the opposite angles are equal and the diagonals bisect each other.

Q2. What is the property of diagonals in a kite?

Ans. In a kite, one diagonal bisects the other at right angles.

Q3. What is a trapezium?

Ans. A trapezium is a quadrilateral in which one pair of opposite sides is parallel.

Q4. State the properties of a rectangle.

Ans. In a rectangle, the opposite sides are equal and parallel, each angle is 90Β° and the diagonals are equal and bisect each other.

Q5. What is the mid-point theorem related to quadrilaterals?

Ans. The mid-point theorem states that the line joining the midpoints of two sides of a triangle is parallel to the third side and equal to half of it. This result is often applied in solving problems related to quadrilaterals.

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