A battery of 9 V is connected in series with resistors of 0.2 Ω, 0.3 Ω, 0.4Ω, 0.5Ω and 12Ω, respectively. How much current would flow through the 12Ωresistor?
Here, V = 220 V, I = 5 A
Let the number of resistors be n
Resistance of circuit R = V/I
R = 220/5
R = 44Ω
Resistance of each resistor r = 176 W
For n resistors, if the resistance of each is r is connected in parallel, the resultant resistance R is :
R = r/n ⇒ 44
176/n ⇒ 176/44
n = 4
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