Chapter 11

NCERT
Class 10
Science
Solutions
10. How many 176 Ω resistors (in parallel) are required to carry 5 A on a 220 V line?

Question:

A battery of 9 V is connected in series with resistors of 0.2 Ω, 0.3 Ω, 0.4Ω, 0.5Ω and 12Ω, respectively. How much current would flow through the 12Ωresistor?

Answer:

Here, V = 220 V, I = 5 A

Let the number of resistors be n

Resistance of circuit R = V/I

R = 220/5

R = 44Ω

Resistance of each resistor r = 176 W

For n resistors, if the resistance of each is r is connected in parallel, the resultant resistance R is :

R = r/n ⇒ 44

176/n ⇒ 176/44

n = 4

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