Chapter 11

NCERT
Class 10
Science
Solutions
2. An electric lamp of 100 Ω, a toaster of resistance 50 Ω, and a water filter of resistance 500 Ω are connected in parallel to a 220 V source. What is the resistance of an electric iron connected to the same source
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Question:

An electric lamp of 100 Ω, a toaster of resistance 50 Ω, and a water filter of resistance 500 Ω are connected in parallel to a 220 V source. What is the resistance of an electric iron connected to the same source that takes as much current as all three appliances, and what is the current through it?

Answer:

Resistance (R1) of an electric lamp = 100Ω

Resistance (R2) of of toaster = 50Ω

Resistance (R3) of water filter = 500Ω

A potential difference of the source (V) = 220V

The resistors are connected in series. 

Total resistance in electric iron

1/R= 1/R1 + 1/R2 + 1/R3

1/R = 1/100 + 1/50 + 1/500

1/R = (5+10+1)/500

R = 500/16 Ω

R = 31.25 Ω

As per Ohm's law

R = V/I

31.25 Ω = 220 V/I

I = 220 V X 100 / 3125

I = 7.04 A

Resistance is 31.25 Ω and current is 7.04 A.

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