Chapter 11

NCERT
Class 10
Science
Solutions
9. A battery of 9 V is connected in series with resistors of 0.2Ω, 0.3Ω, 0.4Ω, 0.5Ω and 12Ω, respectively. How much current would flow through the 12Ω resistor?

Question:

A battery of 9 V is connected in series with resistors of 0.2 Ω, 0.3 Ω, 0.4Ω, 0.5Ω and 12Ω, respectively. How much current would flow through the 12Ωresistor?

Answer:

The resistance is connected in series

RS = 0.2Ω + 0.3Ω + 0.4Ω + 0.5Ω + 12Ω

RS = 13.4Ω

Current = I = V/RS

I = 9/13.4

I = 0.67A

So, the current flowing through 12 W resistor = 0.67 A.

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