Chapter 11

NCERT
Class 10
Science
Solutions
1. Judge the equivalent resistance when the following (a) 1 Ω and 106 Ω, (b) 1 Ω and 103 Ω and 106 Ω

Question:

Judge the equivalent resistance when the following (a) 1 Ω and 106 Ω, (b) 1 Ω and 103 Ω and 106 Ω.

Answer:

(a) When resistance is arranged in parallel,

1/RP = 1/R1 + 1/R2

1/RP = 1/1 + 1/106

1/RP = (106+1)/ 106

RP  = 106/ (106+1) ~ 106/ (106

RP = 1Ω

(b)Similarly,

1/RP = 1/R1 + 1/R2 + 1/R3

1/RP = 1/ 1+ 1/103 + 1/106

1/RP = (106+103+1)/ 106

RP = 106/(106+103+1)

RP  = 1000000/1001001

RP  = RP = 0.999Ω

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