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A ball is thrown vertically upwards with a velocity of 49 m/s Calculate.
(i) The maximum height to which it rises.
(ii) The total time it takes to return to the surface of the earth.
According to question, u = 49 m/s
at the maximum height
v = 0, g = 9.8 m/s2
(i) From the equation
v2 = u2 – 2gh
0 = (49)2 - 2 x 9.8 x h
19.6h = 49 x 49
h = (49 x 49) / 19.6
h = 122.5 m
(ii) While throwing upward
v = u - gt
t = (u-v)/(-g)
t = -49/-9.8
t = 5s
∵ The ball takes the same time to reach the surface from the maximum height
∴ total time = (5 + 5)s = 10s
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