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A farmer moves along the boundary of a square field of side 10 m in 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position?
Total distance traveled by farmer in
40s = 4×10 =40m
Total time taken =2 min×20 sec =140 sec
Total number of rounds =140/40 =3.5
If the farmer starts from A, then after 3.5 rounds, he reaches to point ′C′.
Therefore, displacement =AC.
Now, ABCD is a square, then △AB is a right-angled △.
Using Pythagoras theorem,
AC2=AB2+BC2⇒AC=√102+102=√200=10√2
AC= 10×1.414=14.14m
Hence, displacement =14.14m
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