NCERT Textbook Class 11 Mathematics 2026-27 | Download Free PDF

The NCERT Class 11 Mathematics textbook for the academic year 2026-27 is considered the most essential study resource by CBSE. 

The book is designed according to the latest CBSE curriculum and focuses on building strong conceptual understanding and problem-solving skills. It covers a wide range of topics including algebra, calculus, geometry, and statistics, which form the base for higher-level mathematics in Class 12.

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Maths Class 11 NCERT textbook PDF (2026-27)

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Overview for Class 11 NCERT Mathematics Textbook

The Class 11 Mathematics NCERT textbook plays a crucial role in developing analytical thinking and logical reasoning among students. It introduces fundamental concepts that are essential for advanced topics in Class 12 and competitive exams. 

With a structured approach, the book helps students understand formulas, theorems, and their real-life applications. Regular practice of NCERT problems strengthens conceptual clarity and improves accuracy in solving numerical questions.

Key Highlights for NCERT Class 11 Mathematics 

These are some of the key highlights that make NCERT Mathematics a trusted resource:

• Based on the latest CBSE syllabus for 2026-27
• Covers fundamental concepts of algebra, calculus, and geometry
• Focuses on step-by-step problem-solving approach
• Includes a variety of exercise questions for practice
• Builds a strong foundation for Class 12 and competitive exams 

NCERT Class 11 Mathematics textbook Chapters 

The latest 2026-27 edition of the Class 11 Maths NCERT textbook is available on the official NCERT website. Below is the complete list of chapters:

• Chapter 1. Sets: Introduces the concept of sets, types of sets, and basic operations like union and intersection.
• Chapter 2. Relations and Functions: Explains ordered pairs, relations, and different types of functions.
• Chapter 3. Trigonometric Functions: Covers trigonometric ratios, identities, and their applications.
• Chapter 4. Complex Numbers and Quadratic Equations: Introduces complex numbers and methods to solve quadratic equations.
• Chapter 5. Linear Inequalities: Focuses on solving inequalities and representing them graphically.
• Chapter 6. Permutations and Combinations: Deals with counting principles and arrangements of objects.
• Chapter 7. Binomial Theorem: Explains expansion of expressions using binomial theorem.
• Chapter 8. Sequences and Series: Covers arithmetic and geometric progressions.
• Chapter 9. Straight Lines: Introduces coordinate geometry concepts related to straight lines.
• Chapter 10. Conic Sections: Explains circles, parabolas, ellipses, and hyperbolas.
• Chapter 11. Introduction to Three-Dimensional Geometry: Introduces basic 3D geometry concepts and coordinate system.
• Chapter 12. Limits and Derivatives: Provides an introduction to calculus concepts.
• Chapter 13. Statistics: Focuses on data collection, representation, and analysis.
• Chapter 14. Probability: Introduces basic probability concepts and calculations.

Class 11 NCERT Mathematics Study Material

NCERT provides comprehensive study material for Class 11 Mathematics that helps students build a strong conceptual base. Consistent practice of textbook exercises is essential for mastering the subject.

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Chapters Deleted from Class 11 NCERT Mathematics 

As per NCERT guidelines, the current textbook will continue for the academic session 2026-27. Any major revisions or changes are expected in upcoming sessions as per NEP implementation.

Most Asked Question for Class 11 NCERT Mathematics Textbook 

These are some of the important questions from NCERT Class 11 Mathematics which are frequently asked in the exams. 

Chapter 2: Relations and Functions 

Q1. If the set A has 3 elements and the set B = {3,4,5}, then find the number of elements in (A x B) ? 

Ans. We are provided with the fact that the set A has 3 elements and the set B is given as {3,4,5} . 

So, the number of elements in set B is 3 . 

Thus, the number of elements in (A×B) will be, 

= Number of elements in A× Number of elements in B 

= 3×3 = 9 

So, the number of elements in (A× B) is 9.

Q2. State whether each of the following statements are true or false. If the statement is false, rewrite the given statement correctly. 

(i) If P={m,n} and Q={n,m} , then P×Q={(m,n),(n,m)} . 

Ans: The statement is False. 

We have the values as, P ={m,n} and Q = {n,m}. 

Thus, P×Q = {(m, m),(m, n),(n, m),(n, n)} 

The statement is true. 

(ii) If A and B are non-empty sets, then A×B is a non-empty set of ordered pairs (x,y) such that x∈A and y∈B . 

Ans: The statement is False. 

We have the values as, P ={m,n} and Q = {n,m}. 

Thus, P×Q = {(m, m),(m, n),(n, m),(n, n)} 

The statement is true.

(iii) If A={1,2},B={3,4} , then A×{B ∩ ∅}=∅ . 

Ans: The statement is True. 

We know, B∩∅ = ∅ 

Thus, we have, A×{B∩∅} = A×∅ = ∅.

Chapter 3: Trigonometric Functions 

Q1. A wheel makes 360 revolutions in one minute. Through how many radians does it turn in one second? 

Ans. Number of revolutions the wheel makes in 1 minute = 360

Number of revolutions the wheel makes in 1 second = 360/60 = 6 

In one complete revolution, the wheel turns at an angle of 2π radians. 

Therefore, in 6 revolutions, the angle turned = 6×2π=12π radians. 

Hence, the wheel turns at an angle of 12π radians in one second.

Chapter 5: Linear Equalities 

Q1. Solve the given inequality for real x : 2(2x + 3) −10 < 6(x − 2) 

Ans. 2(2x + 3) −10 < 6(x − 2)
⇒4x +6−10 < 6x −12 

⇒ 4x − 4 < 6x −12 

⇒ −4 +12 < 6x − 4x 

⇒8 < 2x 

⇒4 < x 

As a result, any real numbers x bigger than 4 are solutions to the specified inequality. As a result, the given inequality's solution set is (4,−∞).

Q2. Find all pairs of consecutive even positive integers, both of which are larger than 5 such that their sum is less than 23 . 

Ans. Let be the smaller of the two even positive integers that follow. The other integer is x + 2 

because both integers are greater than 5, x > 5……(1) 

Also, the sum of the two integers is less than 23 x + (x + 2) < 23 

⇒ 2x + 2 < 23 

⇒ 2x < 23− 2 

⇒2x < 21 

⇒ x < 21/2

⇒ x < 10.5……(2) 

From (1) and (2) , we obtain 5 < x <10.5 

Because x is an even number, it can have any of the following values: 6,8,10. As a result, the required pairs are (6,8),(8,10) and (10,12) .

Chapter 7: Binomial Theorem 

Q1. Expand the expression (2x − 3)⁶.

Ans. By using Binomial Theorem, the expression (2x − 3)⁶ can be expanded as 

   (2x − 3)⁶=⁶ C (2x)⁶ −⁶C (2x)⁵(3) +⁶ C (2x)⁴(3)² 

   -⁶C₃ (2x)³(3)³ - ⁶C₄(2x)²(3)⁴ - ⁶C₅ (2x)² (3)⁴ - ⁶C₆ (3)⁶

= 64x⁶ - (32x⁵) (3) + 15 (16x⁴) (9) - 20 (8x³) (27) + 15(4x²)(81) - 6(2x) (243) + 729

= 64x⁶ − 576x⁵ + 2160x⁴ − 4320x³ + 4860x² − 2916x + 729

Chapter 10: Conic Sections 

Q1. Find the equation of the circle passing through the points (4,1) and (6,5) and whose centre is on the line 4x + y = 16 

Ans: Let the equation of the required circle be (x − h)² + (y − k)² = r² 

Since the circle passes through points (4,1) and (6,5), 

  (4 − h)² + (1− k)² = r²      − h)² + (5 − k)² = r² 

………(i) 

………(ii) 

Since the centre (h,k) of the circle lies on line 4x + y =16, 

4h + k =16                       ………(iii) 

 From equations (i) and (ii), we get 

⇒ (4 − h)² + (1− k)² = (6 − h)² + (5 − k)² 

⇒16 − 8h + h² +1− 2k + k² = 36 −12h + h² + 25 −10k + k² 

⇒16 − 8h +1− 2k = 36 −12h + 25 −10k 

⇒ 4h + 8k = 44 

⇒ h + 2k =11                    ………(iv) 

On solving equations (iii) and (iv), we obtain h = 3 and k = 4 

On substituting the values of h and k in equation (i), we obtain 

(4 − 3)² + (1− 4)² = r² 

⇒ (1)² + (−3)² = r² 

⇒1+ 9 = r

Chapter 14: Probability 

Q1.  The numbers 1 , 2 , 3 and 4 are written separately on four slips of paper. The slips are put in a box and mixed thoroughly. A person draws two slips from the box, one after the other, without replacement. Describe the sample space for the experiment.

Ans. If 1 appears on the first drawn slip, then the possible numbers to appear on the second drawn slip are 2 , 3 , or 4 . Similarly, if 2 appears on the first drawn slip, then the possible numbers to appear on the second drawn slip are 1 , 3 , or 4 . The same holds true for the remaining numbers also. 

Thus, the sample space of this experiment is obtained as: 

S = {(1,2),(1,3),(1,4),(2,1),(2,3),(2,4),(3,1),(3,2),(3,4),(4,1),(4,2),(4,3)} 

Effective Preparation Tips: NCERT Class 11 Mathematics textbook 

Preparing for Class 11 Mathematics requires regular practice and conceptual clarity. The following tips can help:

• Build Concept and Apply Immediately: Don’t just read theory. After every concept, solve 4-5 questions instantly to lock understanding.
• Must Do NCERT Examples: Most students skip examples, but don’t. They are the blueprint for solving exercise questions and exams.
• Follow the “3-Level Practice Rule”: 1st round: Solve basic questions; 2nd round: Attempt without help; 3rd round: Time-bound practice.
• Create a Mistake Notebook: Note down wrong questions and why you got them wrong. This is more powerful than solving 100 new questions. 
• Focus more in high-weight chapters: Prioritise chapters like Trigonometry, Algebra (P&C, Binomial), and Calculus basics (Limits & Derivatives).
• Don’t Memorise: Especially for Coordinate Geometry and Trigonometry, try to understand graphs and patterns instead of rote learning.
• Weekly Revision is Important: Maths is not a one-time subject. Revise concepts every week to avoid forgetting formulas and methods. 
• Solve Without Looking at Solutions: Struggling is part of learning. Avoid jumping to solutions too quickly-this builds real problem-solving ability. 
• Mix Chapters While Practicing: Don’t practice one chapter in isolation. Mixed practice improves application skills for exams. 

FAQs

Q1. Which chapters in Class 11 Maths NCERT are most important for building a strong base for Class 12?

Ans. Chapters like Trigonometric Functions, Sequences & Series, Limits & Derivatives, and Straight Lines are extremely important as they are directly used in Class 12 topics like calculus, vectors, and 3D geometry.

Q2. Why do students find Class 11 Maths difficult compared to Class 10?

Ans. Class 11 Maths introduces abstract concepts and requires deeper understanding rather than formula-based solving. The shift from basic to advanced problem-solving makes it challenging initially.

Q3. Is solving only NCERT exercises enough to score well in school exams?

Ans. For school exams, NCERT exercises and examples are usually sufficient. However, for higher accuracy and confidence, students should also practice additional mixed and application-based questions. 

Q4. What is the best strategy to avoid mistakes in Maths exams?

Ans. Practice regularly, maintain a mistake notebook, revise formulas frequently, and avoid rushing during exams to minimize calculation and conceptual errors.

Q5. What is the biggest mistake students make while preparing for Class 11 Mathematics?

Ans. The most common mistake is focusing only on solving questions without understanding the underlying concepts, which leads to confusion in advanced problems.