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The far point of a myopic person is 80 cm in front of the eye. What is the nature and power of the lens required to correct the problem?
Power of lens = 1/f
∴ f = -80 cm
P = 1/f
P = -100/80
P = -5/4
P = -1.25 D
For correction of the defect, the lens should be concave, because power is negative.
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