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An object 5 cm long is placed at a distance of 25 cm from a converging lens of focal length 10 cm. Find the position, size and nature of the image formed along with the ray diagram.
Here,
h = 5cm = Height of image, h′ = Height of image = ?, u = – 25 cm, f = + 25 cm, v = ?
Using Lens formula :
1/v - 1/u = 1/f
1/v = 1/f + 1/u
1/v = 1/10 + 1/(-25)
1/v = 1/10 - 1/25
1/v = 5-2/50
1/v = 3/50
v = 50/3
∴ v = 16.6 cm
v = positive. This implies that the image formed at a distance of 16.6 cm behind the mirror is real and inverted.
Power of lens
m = h'/h = v/u
h' = v/u x h
h' = 50/3 x 1/(-25) x 5
h' = -3.33
h′ = negative. Thus, the image formed is inverted.
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