Here I = ?, R = ?, P = 2kW = 2 × 10³ W, V = 220 V

Using formula, P = V² / R

⇒ R = V² / P

R = (220 X 220) / (2 X 10³)

R = (484 X 10²) / (2 X 10³)

R = 242 X 10^-1

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Using formula V = IR

I = V/R

I = 220 x 10/ 242

I = 2200 / 242

I= 9.09A

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The current (9.09 A) exceeds the fuse rating (5 A) of the given circuit. Due to this, the fuse is broken due to the high flow of current through the circuit.