Chapter 3
The World of Numbers
CBSE Class 9
Mathematics Solutions
Educart Mathematics class Class 9 NCERT Exemplar cover
Question:

Try to find the decimal expansions of 103\frac{10}{3} and 1112\frac{11}{12}. What do you observe about the repetition of the digits after the decimal point? [Page No. 57]

Answer: Verified

Doing the long division:

103=3.3333=3.3\frac{10}{3}=3.3333\dots=3.\overline{3} (the bar means 33 repeats forever, right from the start).

1112=0.91666=0.916\frac{11}{12} = 0.91666 \dots = 0.91\overline{6} (the digits 9191 appear once, then 66 repeats forever).

Observation: both are non-terminating repeating decimals, but the repeating part starts in different places. In 103\frac{10}{3} the repetition begins immediately after the point (a pure repeating decimal). In 1112\frac{11}{12} there are a couple of non-repeating digits first, then the repeating block (a mixed repeating decimal). Neither terminates, because their denominators (3, and 12=22×312 = 2^2 \times 3) contain the prime 3, a prime other than 2 or 5.

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