Question: Find the quotient: (A) 23÷310\frac{2}{3} \div \frac{3}{10}32÷103 (B) 711÷58\frac{7}{11} \div \frac{5}{8}117÷85 (C) −47÷514 [Page No. 49]-\frac{4}{7} \div \frac{5}{14} \text{ [Page No. 49]}−74÷145 [Page No. 49] Answer: Verified (A) (23)÷(310):23×103=209\text{(A) }\left(\frac{2}{3}\right)\div\left(\frac{3}{10}\right):\frac{2}{3}\times\frac{10}{3}=\frac{20}{9}(A) (32)÷(103):32×310=920 (B)(711)÷(58):711×85=5655(B)\left(\frac{7}{11}\right)\div\left(\frac{5}{8}\right):\frac{7}{11}\times\frac{8}{5}=\frac{56}{55}(B)(117)÷(85):117×58=5556 (C)(−47)÷(514):−47×145=−5635=−85(C)\left(\frac{-4}{7}\right)\div\left(\frac{5}{14}\right):\frac{-4}{7}\times\frac{14}{5}=\frac{-56}{35}=\frac{-8}{5}(C)(7−4)÷(145):7−4×514=35−56=5−8