Chapter 3
The World of Numbers
CBSE Class 9
Mathematics Solutions
Educart Mathematics class Class 9 NCERT Exemplar cover
Question:

Find the product:

(A) 23×310\frac{2}{3} \times \frac{3}{10}

(B) 711×58\frac{7}{11} \times \frac{5}{8}

(C) 47×514 [Page No. 49]-\frac{4}{7} \times \frac{5}{14} \text{ [Page No. 49]}

Answer: Verified

(A) (23)×(310):630=15\text{(A) }\left(\frac{2}{3}\right)\times\left(\frac{3}{10}\right):\frac{6}{30}=\frac{1}{5}

(B)(711)×(58):3588(B) \left(\frac{7}{11}\right) \times \left(\frac{5}{8}\right): \frac{35}{88}

(C)(47)×(514):2098=1049(C) \left(\frac{-4}{7}\right) \times \left(\frac{5}{14}\right): \frac{-20}{98} = \frac{-10}{49}

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