Question: Find the product: (A) 23×310\frac{2}{3} \times \frac{3}{10}32×103 (B) 711×58\frac{7}{11} \times \frac{5}{8}117×85 (C) −47×514 [Page No. 49]-\frac{4}{7} \times \frac{5}{14} \text{ [Page No. 49]}−74×145 [Page No. 49] Answer: Verified (A) (23)×(310):630=15\text{(A) }\left(\frac{2}{3}\right)\times\left(\frac{3}{10}\right):\frac{6}{30}=\frac{1}{5}(A) (32)×(103):306=51 (B)(711)×(58):3588(B) \left(\frac{7}{11}\right) \times \left(\frac{5}{8}\right): \frac{35}{88}(B)(117)×(85):8835 (C)(−47)×(514):−2098=−1049(C) \left(\frac{-4}{7}\right) \times \left(\frac{5}{14}\right): \frac{-20}{98} = \frac{-10}{49}(C)(7−4)×(145):98−20=49−10