Find the $10^{\text{th}}$ and $n^{\text{th}}$ terms of the G.P.: 5, 25, 125, ...                                                                               [Page No. 193]

$$\text{Here, }a=5,r=\frac{25}{5}=5$$

General term: $T_n = ar^{n-1}$

$$T_n = 5(5^{n-1}) = 5^n$$

$$\text{So, } T_n = 5^n$$

$$10^{\text{th}} \text{ term: } T_{10} = 5^{10} = 9765625$$

Hence, 10th term is 9765625.

Concept Applied
The nth term of a GP with first term $a$ and common ratio $r$ is $T_n = ar^{n-1}$.