The variation of density of medium for a sound wave propagating with a speed of 340 ms⁻¹ is shown in the given figure. Calculate the wavelength and frequency of the sound wave.

From the figure it is concluded that, the distance between two consecutive compressions is 4 cm, which represents one wavelength.

Therefore, λ = 4 cm = 0.04 m

Speed of sound,

$$v = 340 \text{ ms}^{-1}$$

Using the relation:

$$v = v\lambda$$

$$v = \frac{v}{\lambda}$$

$$v = \frac{340}{0.04}$$

$$v = 8500 \text{ Hz}$$

Therefore,

Wavelength = 4 cm

Frequency = 8500 Hz