Question:
Prove that the perpendicular bisector of a chord passes through the centre of the circle.
Answer:
Verified
Let AB be a chord of a circle with centre O.

Since OA = OB (both are radii), O is equidistant from A and B.
Therefore, O lies on the perpendicular bisector of AB (by the locus property of the perpendicular bisector).
Hence, the perpendicular bisector of the chord AB passes through the centre O.