On a seesaw with sliding seats, a child is sitting on one side and an adult on the other side. The adult weighs twice that of the child. The seesaw however is balanced. Draw a figure which depicts this situation showing the distances from the fulcrum where the child and the adult are seated.

Since the adult weighs twice as much as the child, the adult must sit at half the distance from the fulcrum compared to the child for the seesaw to balance.

Load $\times$ Distance = Effort $\times$ Distance

If child's weight = $W$ and distance = $2d$

Adult's weight = $2W$ and distance = $d$

Then, $W \times 2d = 2W \times d$

So, the seesaw remains balanced.

Weight: Adult = $2 \times$ Child

The child sits farther from the fulcrum, while the heavier adult sits closer to the fulcrum.