Chapter 7
The Mathematics of Maybe: Introduction to Probability
CBSE Class 9
Mathematics Solutions
Educart Mathematics class Class 9 NCERT Exemplar cover
Question:

A teacher mixes a large bag of sweets of different colours and randomly selects a sample of 30 sweets.
She counts the number of sweets of each colour:
10 red sweets
8 green sweets
7 yellow sweets
5 blue sweets

(A) Calculate the probability that a randomly picked sweet from the sample is green.

(B) If there are 600 sweets in total in the large bag, estimate how many are likely to be yellow, based on the sample results.                                                                                                                                                                                   [Page No. 165]

Answer: Verified

(A) P(green)=Number of green sweetsTotal number of sweetsP(\text{green}) = \frac{\text{Number of green sweets}}{\text{Total number of sweets}}

=830=415= \frac{8}{30} = \frac{4}{15}

(B) P(yellow)=Number of yellow sweetsTotal number of sweetsP(\text{yellow}) = \frac{\text{Number of yellow sweets}}{\text{Total number of sweets}}

=730= \frac{7}{30}

Estimated number of yellow sweets in 600 sweets is 730×600\frac{7}{30} \times 600

=7×20=140 sweets.= 7 \times 20 = 140 \text{ sweets.}

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