A game of chance consists of spinning an arrow (see given figure) which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8, and these are equally likely outcomes. What is the probability that it will point at

(A) 8?

(B) An odd number?

(C) A number greater than 2?

(D) A number less than 9?

(E) A multiple of 3?

(A) $P(8) = \frac{1}{8}$

(B) Odd numbers: {1, 3, 5, 7} = 4 outcomes.

$$P(\text{odd}) = \frac{4}{8} = \frac{1}{2}$$

(C) Numbers greater than 2 = {3, 4, 5, 6, 7, 8} = 6 outcomes.

$$P(\text{number greater than } 2) = \frac{6}{8} = \frac{3}{4}$$

(D) Numbers less than 9 = {1, 2, 3, 4, 5, 6, 7, 8} = 8 outcomes.

$$P(\text{number less than } 9) = \frac{8}{8} = 1$$

(E) Multiples of 3 = {3, 6} = 2 outcomes.

$$P(\text{multiple of } 3) = \frac{2}{8} = \frac{1}{4}$$