Question:

The probability of getting a number which is neither prime nor composite in single throw of a dice is:

(a) $\frac{1}{3}$

(b) $\frac{1}{6}$

(c) $\frac{2}{5}$

(d) $\frac{1}{2}$

Answer: Verified

Ans. (b) $\frac{1}{6}$

Explanation: Of the six numbers, only one number, i.e., 1 is neither prime nor composite.

So, P(neither prime nor composite) = $\frac{1}{6}$

The probability of getting a number which is neither prime nor composite in single throw of a dice is: (a) 13\frac{1}{3}31​ (b) 16\frac{1}{6}61​ (c) 25\frac{2}{5}52​ (d) 12\frac{1}{2}21​