Chapter 2
Introduction to Linear Polynomials
CBSE Class 9
Mathematics Solutions
Educart Mathematics class Class 9 NCERT Exemplar cover
Question:

Using the expression 2n12n - 1, can you find out how many tiles will be there in the 15th15^{\text{th}} stage and the 26th26^{\text{th}} stage of the pattern? Also, which stage will contain 21 tiles and 47 tiles?                                                                    [Page No. 22]

Answer: Verified

The rule for the number of tiles at Stage nn is 2n12n - 1.

15th15^{\text{th}} stage: 2×151=292 \times 15 - 1 = 29 tiles.

26th26^{\text{th}} stage: 2×261=512 \times 26 - 1 = 51 tiles.

To find which stage has a given number of tiles, set 2n12n - 1 equal to it and solve for nn:

• 21 tiles: 2n1=212n=22n=112n - 1 = 21 \rightarrow 2n = 22 \rightarrow n = 11.
Hence, Stage 11.

• 47 tiles: 2n1=472n=48n=242n - 1 = 47 \rightarrow 2n = 48 \rightarrow n = 24.
Hence, Stage 24.

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