Chapter 6
Measuring Space: Perimeter and Area
CBSE Class 9
Mathematics Solutions
Educart Mathematics class Class 9 NCERT Exemplar cover
Question:

Use the above to make a conjecture about the area occupied by circles fitted into a rectangle in the manner shown. Test your conjecture for particular cases: 10 circles; 20 circles; 50 circles. Then prove your conjecture!

Answer: Verified

Let there be nn equal circles of radius rr arranged in a row inside a rectangle.

Then:

Rectangle height = 2r2r

Rectangle width = 2nr2nr

Therefore,

Area of rectangle = (2r)(2nr)=4nr2(2r)(2nr) = 4nr^2

Total area of the π\pi circles:

n(πr2)=nπr2n(\pi r^2) = n\pi r^2

Hence, Area occupied by circlesArea of rectangle=nπr24nr2=π4\frac{\text{Area occupied by circles}}{\text{Area of rectangle}} = \frac{n\pi r^{2}}{4nr^{2}} = \frac{\pi}{4}

Thus, irrespective of the number of circles,

Area occupied by circles = π4\frac{\pi}{4} of the rectangle

Hence, proved.

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