Try and find other patterns like this one (Refer to NCERT page no. 68). For example, you could consider 4 consecutive squares and see if you can find a pattern. [Page No. 69]

Pattern in Four Consecutive Squares

For any four consecutive perfect squares,

(first + fourth) - (second + third) = 4

Let the squares be $a^2, (a + 1)^2, (a + 2)^2, (a + 3)^2$.

Then,

$$[a^2 + (a + 3)^2] - [(a + 1)^2 + (a + 2)^2] = 4.$$

The variable terms cancel out, leaving the constant value 4 every time.

For example, $(1 + 16) - (4 + 9) = 17 - 13 = 4$.

Thus, this pattern holds for every set of four consecutive perfect squares.