Question: The length of the minute hand of a clock is 7 cm. Find the area swept by the minute hand in 10 minutes. [Page No. 148] Answer: Verified In 60 minutes, minute hand completes a full circle (360∘360^\circ360∘). In 10 minutes, angle swept = 1060×360∘=60∘\frac{10}{60} \times 360^\circ = 60^\circ6010×360∘=60∘ Radius = 7 cm Area swept=πr2×θ360∘=227×72×60360=227×49×16\begin{aligned} \text{Area swept} &= \pi r^2 \times \frac{\theta}{360^\circ} \\ &= \frac{22}{7} \times 7^2 \times \frac{60}{360} \\ &= \frac{22}{7} \times 49 \times \frac{1}{6} \end{aligned}Area swept=πr2×360∘θ=722×72×36060=722×49×61 1546=773≈25.67 cm2\frac{154}{6} = \frac{77}{3} \approx 25.67 \text{ cm}^{2}6154=377≈25.67 cm2