Chapter 2
Introduction to Linear Polynomials
CBSE Class 9
Mathematics Solutions
Educart Mathematics class Class 9 NCERT Exemplar cover
Question:

Look at the first three stages of a growing pattern of hexagons made using matchsticks. A new hexagon gets added at every stage which shares a side with the last hexagon of the previous stage.

Question image

(A) Draw the next two stages of the pattern. How many matchsticks will be required at these stages?

(B) Complete the following table.

Stage Number Number of matchsticks
11
22
33
44
55
......
nn

(C) Find a rule to determine the number of matchsticks required for the nthn^{\text{th}} stage.

(D) How many matchsticks will be required for the 15th15^{\text{th}} stage of the pattern?

(E) Can 200 matchsticks form a stage in this pattern? Justify your answer.

Answer: Verified

Stage 1: one hexagon 6 matchsticks.

Stage 2: two hexagons sharing a side \rightarrow 6+5=116 + 5 = 11 matchsticks.

Stage 3: three hexagons \rightarrow 11+5=1611 + 5 = 16 matchsticks.

Each new stage adds 5 matchsticks.

Stage 4: 4×5+1=214 \times 5 + 1 = 21 matchsticks.

Stage 5: 21+5=2621 + 5 = 26 matchsticks

(A)

Answer image

(B) Table of values:

Stage number Number of Matchsticks
1 6
2 11
3 16
4 21
5 26
... ...
nn 5n+15n + 1

(C) General rule: Number of matchsticks = 5n+15n + 1

(D) 15th15^{\text{th}} stage: 5(15)+1=765(15) + 1 = 76 matchsticks.

(E) 5n+1=2005n + 1 = 200

5n=199\Rightarrow 5n = 199

n=39.8\Rightarrow n = 39.8, which is not a whole number.

So, 200 matchsticks cannot exactly form a stage of this pattern.

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