Chapter 4
Exploring Algebraic Identities
CBSE Class 9
Mathematics Solutions
Educart Mathematics class Class 9 NCERT Exemplar cover
Question:

James and Reshma were talking about algebraic identities they learnt in school.

James: (ab)2(a+b)=(a22ab+b2)(a+b)(a - b)^2(a + b) = (a^2 - 2ab + b^2)(a + b)
Reshma: I have a different idea.

(ab)2(a+b)=(ab)[(ab)(a+b)](a - b)^2(a + b) = (a - b)[(a - b)(a + b)]
=(ab)(a2b2)= (a - b)(a^2 - b^2)

I will find this product to get the answer.
According to you, who is correct and why? Try to combine more such identities and find new results.
[Page No. 82]

Answer: Verified

Both methods are correct because multiplication is associative and commutative, so the factors can be grouped in any order.

James expands (ab)2(a+b)=(a22ab+b2)(a+b)(a - b)^2(a + b) = (a^2 - 2ab + b^2)(a + b), which simplifies to a3a2bab2+b3a^3 - a^2b - ab^2 + b^3.

Reshma first uses the identity (ab)(a+b)=a2b2(a - b)(a + b) = a^2 - b^2, and then multiplies by (ab)(a - b):

(ab)(a2b2)=a3a2bab2+b3.(a - b)(a^2 - b^2) = a^3 - a^2b - ab^2 + b^3.

Thus, both methods give the same result, a3a2bab2+b3a^3 - a^2b - ab^2 + b^3.

Reshma's method is shorter because it applies the difference-of-squares identity before expanding.

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