Find the values of the following using the identity $(a - b)^2 = a^2 - 2ab + b^2$.

(A) $(79)^2$

(B) $(193)^2$

(C) $(299)^2$                             [Page No. 75]

(A) $(80 - 1)^2 = 80^2 - 2 \times 80 \times 1 + 1^2$

$= 6400 - 160 + 1 = 6241$

(B) $(200 - 7)^2 = 200^2 - 2 \times 200 \times 7 + 7^2$

$= 40000 - 2800 + 49 = 37249$

(C) $(300 - 1)^2 = 300^2 - 2 \times 300 \times 1 + 1^2$

$= 90000 - 600 + 1 = 89401$