Chapter 1
Orienting Yourself: The Use of Coordinates
CBSE Class 9
Mathematics Solutions
Educart Mathematics class Class 9 NCERT Exemplar cover
Question:

Can these distances help you find the distance AD? [Page No. 9]

Answer: Verified

Yes. The horizontal and vertical distances can be used to find AD using the Baudhāyana-Pythagoras Theorem.

AD2=42+32=16+9=25AD^2 = 4^2 + 3^2 = 16 + 9 = 25

AD=25=5 unitsAD=\sqrt{25}=5\text{ units}^{}

Therefore, the distance AD = 5 units

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(All Q's of this Chapter solved)
More NCERT Questions
In moving from A(3, 4) to D(7, 1), what distance has been covered along the x-axis? What about the distance along the y-axis? [Page No. 9] What has remained the same and what has changed with this reflection? [Page No. 11] Would these observations be the same if ADM is reflected in the x-axis (instead of the y-axis)? [Page No. 11] What are the x-coordinate and y-coordinate of the point of intersection of the two axes?